Integrand size = 22, antiderivative size = 73 \[ \int x^3 \left (a+b x^2\right )^{3/2} \left (A+B x^2\right ) \, dx=-\frac {a (A b-a B) \left (a+b x^2\right )^{5/2}}{5 b^3}+\frac {(A b-2 a B) \left (a+b x^2\right )^{7/2}}{7 b^3}+\frac {B \left (a+b x^2\right )^{9/2}}{9 b^3} \]
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Time = 0.04 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {457, 78} \[ \int x^3 \left (a+b x^2\right )^{3/2} \left (A+B x^2\right ) \, dx=\frac {\left (a+b x^2\right )^{7/2} (A b-2 a B)}{7 b^3}-\frac {a \left (a+b x^2\right )^{5/2} (A b-a B)}{5 b^3}+\frac {B \left (a+b x^2\right )^{9/2}}{9 b^3} \]
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Rule 78
Rule 457
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int x (a+b x)^{3/2} (A+B x) \, dx,x,x^2\right ) \\ & = \frac {1}{2} \text {Subst}\left (\int \left (\frac {a (-A b+a B) (a+b x)^{3/2}}{b^2}+\frac {(A b-2 a B) (a+b x)^{5/2}}{b^2}+\frac {B (a+b x)^{7/2}}{b^2}\right ) \, dx,x,x^2\right ) \\ & = -\frac {a (A b-a B) \left (a+b x^2\right )^{5/2}}{5 b^3}+\frac {(A b-2 a B) \left (a+b x^2\right )^{7/2}}{7 b^3}+\frac {B \left (a+b x^2\right )^{9/2}}{9 b^3} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.77 \[ \int x^3 \left (a+b x^2\right )^{3/2} \left (A+B x^2\right ) \, dx=\frac {\left (a+b x^2\right )^{5/2} \left (-18 a A b+8 a^2 B+45 A b^2 x^2-20 a b B x^2+35 b^2 B x^4\right )}{315 b^3} \]
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Time = 2.78 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.67
method | result | size |
pseudoelliptic | \(-\frac {2 \left (-\frac {5 x^{2} \left (\frac {7 x^{2} B}{9}+A \right ) b^{2}}{2}+a \left (\frac {10 x^{2} B}{9}+A \right ) b -\frac {4 a^{2} B}{9}\right ) \left (b \,x^{2}+a \right )^{\frac {5}{2}}}{35 b^{3}}\) | \(49\) |
gosper | \(-\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}} \left (-35 b^{2} B \,x^{4}-45 A \,b^{2} x^{2}+20 B a b \,x^{2}+18 a b A -8 a^{2} B \right )}{315 b^{3}}\) | \(53\) |
default | \(B \left (\frac {x^{4} \left (b \,x^{2}+a \right )^{\frac {5}{2}}}{9 b}-\frac {4 a \left (\frac {x^{2} \left (b \,x^{2}+a \right )^{\frac {5}{2}}}{7 b}-\frac {2 a \left (b \,x^{2}+a \right )^{\frac {5}{2}}}{35 b^{2}}\right )}{9 b}\right )+A \left (\frac {x^{2} \left (b \,x^{2}+a \right )^{\frac {5}{2}}}{7 b}-\frac {2 a \left (b \,x^{2}+a \right )^{\frac {5}{2}}}{35 b^{2}}\right )\) | \(96\) |
trager | \(-\frac {\left (-35 B \,x^{8} b^{4}-45 A \,x^{6} b^{4}-50 B \,x^{6} a \,b^{3}-72 A a \,b^{3} x^{4}-3 B \,a^{2} b^{2} x^{4}-9 A \,a^{2} b^{2} x^{2}+4 B \,a^{3} b \,x^{2}+18 A \,a^{3} b -8 B \,a^{4}\right ) \sqrt {b \,x^{2}+a}}{315 b^{3}}\) | \(101\) |
risch | \(-\frac {\left (-35 B \,x^{8} b^{4}-45 A \,x^{6} b^{4}-50 B \,x^{6} a \,b^{3}-72 A a \,b^{3} x^{4}-3 B \,a^{2} b^{2} x^{4}-9 A \,a^{2} b^{2} x^{2}+4 B \,a^{3} b \,x^{2}+18 A \,a^{3} b -8 B \,a^{4}\right ) \sqrt {b \,x^{2}+a}}{315 b^{3}}\) | \(101\) |
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Time = 0.26 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.36 \[ \int x^3 \left (a+b x^2\right )^{3/2} \left (A+B x^2\right ) \, dx=\frac {{\left (35 \, B b^{4} x^{8} + 5 \, {\left (10 \, B a b^{3} + 9 \, A b^{4}\right )} x^{6} + 8 \, B a^{4} - 18 \, A a^{3} b + 3 \, {\left (B a^{2} b^{2} + 24 \, A a b^{3}\right )} x^{4} - {\left (4 \, B a^{3} b - 9 \, A a^{2} b^{2}\right )} x^{2}\right )} \sqrt {b x^{2} + a}}{315 \, b^{3}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 209 vs. \(2 (65) = 130\).
Time = 0.35 (sec) , antiderivative size = 209, normalized size of antiderivative = 2.86 \[ \int x^3 \left (a+b x^2\right )^{3/2} \left (A+B x^2\right ) \, dx=\begin {cases} - \frac {2 A a^{3} \sqrt {a + b x^{2}}}{35 b^{2}} + \frac {A a^{2} x^{2} \sqrt {a + b x^{2}}}{35 b} + \frac {8 A a x^{4} \sqrt {a + b x^{2}}}{35} + \frac {A b x^{6} \sqrt {a + b x^{2}}}{7} + \frac {8 B a^{4} \sqrt {a + b x^{2}}}{315 b^{3}} - \frac {4 B a^{3} x^{2} \sqrt {a + b x^{2}}}{315 b^{2}} + \frac {B a^{2} x^{4} \sqrt {a + b x^{2}}}{105 b} + \frac {10 B a x^{6} \sqrt {a + b x^{2}}}{63} + \frac {B b x^{8} \sqrt {a + b x^{2}}}{9} & \text {for}\: b \neq 0 \\a^{\frac {3}{2}} \left (\frac {A x^{4}}{4} + \frac {B x^{6}}{6}\right ) & \text {otherwise} \end {cases} \]
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Time = 0.21 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.23 \[ \int x^3 \left (a+b x^2\right )^{3/2} \left (A+B x^2\right ) \, dx=\frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} B x^{4}}{9 \, b} - \frac {4 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} B a x^{2}}{63 \, b^{2}} + \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} A x^{2}}{7 \, b} + \frac {8 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} B a^{2}}{315 \, b^{3}} - \frac {2 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} A a}{35 \, b^{2}} \]
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Time = 0.30 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.00 \[ \int x^3 \left (a+b x^2\right )^{3/2} \left (A+B x^2\right ) \, dx=\frac {35 \, {\left (b x^{2} + a\right )}^{\frac {9}{2}} B - 90 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} B a + 63 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} B a^{2} + 45 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} A b - 63 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} A a b}{315 \, b^{3}} \]
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Time = 5.23 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.32 \[ \int x^3 \left (a+b x^2\right )^{3/2} \left (A+B x^2\right ) \, dx=\sqrt {b\,x^2+a}\,\left (\frac {8\,B\,a^4-18\,A\,a^3\,b}{315\,b^3}+\frac {x^6\,\left (45\,A\,b^4+50\,B\,a\,b^3\right )}{315\,b^3}+\frac {B\,b\,x^8}{9}+\frac {a^2\,x^2\,\left (9\,A\,b-4\,B\,a\right )}{315\,b^2}+\frac {a\,x^4\,\left (24\,A\,b+B\,a\right )}{105\,b}\right ) \]
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